GramToSpoon

5 grams of vanilla extract to teaspoons

Convert 5 grams of vanilla extract to teaspoons for your recipe. Use the result below or try the calculator on the homepage for other amounts.

5 grams of vanilla extract = 1.16 teaspoons

So 5g of vanilla extract is about 1.16 teaspoons.

How we convert 5 grams of vanilla extract to teaspoons

Vanilla Extract has a density of about 4.3 grams per teaspoon. So to convert 5 grams we divide: 5 ÷ 4.3 = 1.16. So 5 grams of vanilla extract equals 1.16 teaspoons.

Vanilla extract is a liquid with a density close to water. One teaspoon weighs about 4.3g.

Other vanilla extract conversions

Need a different amount? Use our conversion calculator to convert any grams of vanilla extract to cups, tablespoons, or teaspoons.